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Orifice Flow

Mechanical Energy Balance

If there is no friction and constant density and no shaft work and no change in elevation, the mechanical energy balance simplifies to:

Incompressible Flow through an Orifice

Thus for incompressible flow, the velocity of the fluid can be determined from the pressure drop across an orifice. Although the flow is usually not frictionless, the velocity can be estimated from the pressure drop and the density of the fluid according to:

m˙=ACd2ρΔP\dot{m} = A C_d \sqrt{2\rho \Delta P}

or

n˙=ACdMw2ρΔP\dot{n} = \frac{A C_d }{M_w} \sqrt{2 \rho \Delta P}

where m˙\dot{m} is the mass flow rate, n˙\dot{n} is the molar flow rate, MwM_w is the molecular weight, AA is the area of the orifice, ρ\rho is the density of the fluid, CdC_d is the discharge coefficient, and ΔP\Delta P is the pressure drop across the orifice. For liquid flow, and estimate of the discharge coefficient is 0.65.

Gaseous flow through an Orifice: General Case

The flow of a gas through an orifice is also derived from an energy balance assuming adiabatic and frictionless flow. The flow is characterized by the pressure ratio, Po/PatmP_o/P_{atm} and associated Mach number, MaMa. PoP_o is the absolute pressure of the volume. The Mach number can be found from:

Ma=min(1,2γ1((PoPatm)γ1γ1))Ma = \text{min} \left(1, \sqrt{\frac{2}{\gamma - 1}\left(\left(\frac{P_o}{P_{atm}}\right)^{\frac{\gamma - 1}{\gamma}} - 1\right)}\right)

where γ\gamma is the ratio of specific heats (1.4 for air). The flow is choked when Ma=1Ma = 1 and unchoked when Ma<1Ma < 1.

The molar flow rate is given by:

n˙=PoACdγRTMwMa[1+(γ1)2Ma2]γ+122γ\dot{n} = P_o A C_d \sqrt{\frac{\gamma}{R T M_w}} Ma \left[ 1+\frac{(\gamma-1)}{2}Ma^2\right]^{\frac{\gamma+1}{2-2\gamma}}

where RR is the gas constant and TT is the temperature, PoP_o is the absolute pressure inside the vessel, CdC_d is the discharge coefficient (typically about 0.9). If you use all SI units (Pascal, meters, kilograms, mole: so pressure in pascal, area in meters, R in J/mol/K, and Mw in kg/mol), you’ll get mole per second for n˙\dot{n}. See Perry’s Handbook for Chemical Engineers Equation 6-118 for more information.

Flashing Two Phase Flow Estimate

m˙=fΔHvAνfg1CpTs\dot{m} = f \frac{\Delta H_v A}{\nu_{fg}}\sqrt{\frac{1}{C_p T_s}}

where m˙\dot{m} is the mass flow rate, ff is a factor depending on the scenario (less than 1), ΔHv\Delta H_v is the heat of vaporization, AA is the area of the orifice, ν\nu is the specific volume change of the liquid as it flashes (νg\nu_g - νl\nu_l), CpC_p is the heat capacity of the fluid, and TsT_s is the saturation temperature of the fluid at the set pressure. See Chapter 4 of Crowl and Louvar for more information.

References
  1. Guymon, C. (2025). Foundations of Spiritual and Physical Safety: with Chemical Processes.